package question21;

/**
 * 21.合并两个有序链表
 * 将两个升序链表合并为一个新的 升序 链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。
 */
// 迭代做法
class Solution {
    public ListNode mergeTwoLists(ListNode list1, ListNode list2) {
        ListNode first = new ListNode(-1);
        ListNode pre = first;
        while(list1 != null &&  list2 != null){
            if(list1.val <= list2.val){
                pre.next = list1;
                list1 = list1.next;
            }else{
                pre.next = list2;
                list2 = list2.next;
            }
            pre = pre.next;
        }
        pre.next = list1 == null ? list2 : list1;
        return first.next;

    }
}

// 递归做法
class Solution2 {
    public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
        if (l1 == null) {
            return l2;
        } else if (l2 == null) {
            return l1;
        } else if (l1.val < l2.val) {
            l1.next = mergeTwoLists(l1.next, l2);
            return l1;
        } else {
            l2.next = mergeTwoLists(l1, l2.next);
            return l2;

        }
    }
}
class ListNode {
     int val;
     ListNode next;
     ListNode() {}
     ListNode(int val) { this.val = val; }
     ListNode(int val, ListNode next) { this.val = val; this.next = next; }
 }
